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Inverse Trigonometric Functions Calculator

Principal values of sin⁻¹, cos⁻¹, tan⁻¹, cot⁻¹, sec⁻¹ and cosec⁻¹ as exact multiples of π, inverses of functions like sin⁻¹(sin 5π/6), and the tan⁻¹x ± tan⁻¹y formula with the ±π correction.

About the Inverse Trigonometric Functions Calculator

Each inverse trigonometric function returns one angle, its principal value: sin⁻¹ in [−π/2, π/2], cos⁻¹ in [0, π], tan⁻¹ in (−π/2, π/2), cot⁻¹ in (0, π), sec⁻¹ in [0, π] without π/2, and cosec⁻¹ in [−π/2, π/2] without 0.

So sin⁻¹(sin θ) equals θ only when θ is in [−π/2, π/2]; sin⁻¹(sin 5π/6) is π/6. tan⁻¹x + tan⁻¹y = tan⁻¹[(x + y)/(1 − xy)] when xy < 1, with π added (x > 0) or subtracted (x < 0) when xy > 1.

The formula

tan⁻¹x + tan⁻¹y = tan⁻¹[(x + y)/(1 − xy)], xy < 1

Principal values

FunctionDomainPrincipal range
sin⁻¹−1 ≤ x ≤ 1[−π/2, π/2]
cos⁻¹−1 ≤ x ≤ 1[0, π]
tan⁻¹every real x(−π/2, π/2)
cot⁻¹every real x(0, π)
sec⁻¹|x| ≥ 1[0, π] except π/2
cosec⁻¹|x| ≥ 1[−π/2, π/2] except 0

Worked example

Example: sin⁻¹(1/2) = π/6

  1. Inputs: I want: A principal value, like sin⁻¹(−√3/2); Function: sin⁻¹; x: 1/2.
  2. Formula: tan⁻¹x + tan⁻¹y = tan⁻¹[(x + y)/(1 − xy)], xy < 1
  3. sin⁻¹: the angle in [−π/2, π/2] whose sin is 1/2: sin⁻¹(1/2) = π/6
  4. Result: sin⁻¹(1/2) = π/6
  5. Principal range: [−π/2, π/2]
  6. Domain: −1 ≤ x ≤ 1
  7. In degrees: 30°

Questions people ask

Why is cos⁻¹(−1/2) = 2π/3 and not −π/3?

cos⁻¹ returns an angle in [0, π], and 2π/3 is the one there with cosine −1/2.

Is sin⁻¹x the same as 1/sin x?

No. sin⁻¹x is the inverse function (arcsin); 1/sin x is cosec x.